(d) $\mathrm{\Delta}p = 2mv = 2 \times 0.25 \times 10 = 5\ kg\ m/s$ $F = \frac{\mathrm{\Delta}p}{\mathrm{\Delta}t} = \frac{5}{0.01} = 500\ N$
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Ph.D. in Physics with 19+ years of teaching experience.