Q.
In the arrangement shown, the pulleys are fixed and ideal, the strings are light, $m_{1} > m_{2}$ and $S$ is a spring balance which is itself massless. The reading of $S$ (in unit of mass) is
A) $m_{1} - m_{2}$
B) $\frac{1}{2}(m_{1} + m_{2})$
C) $\frac{m_{1}m_{2}}{m_{1} + m_{2}}$
D) $\frac{2m_{1}m_{2}}{m_{1} + m_{2}}$
Explanation
(d) Reading of spring balance $= T = \frac{2m_{1}m_{2}g}{m_{1} + m_{2}}(N)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.