Q. A point mass $m$ is moving along inclined plane with acceleration $a$ with respect to smooth triangular block. The triangular block is moving horizontally with acceleration $a_{0}$. The value of $a$ is
A) $g\sin{\theta + a_{0}\cos\theta}$
B) $g\sin{\theta - a_{0}\cos\theta}$
C) $g\cos{\theta - a_{0}\sin\theta}$
D) None of these
Explanation
(b) For discussion of motion of the point mass $m$, we assume that observer is situated at the triangular block. The force diagram of point mass $m$ is shown in figure
From force diagram,
[image:5_image174.jpeg]
$mg\sin\theta - ma_{0}\cos{\theta = ma}$
$\therefore a = g\sin{\theta - a_{0}\cos\theta}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.