A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is ($g/8$), then the ratio of masses is

Question

Dr. Abubacker · Accepted Answer

(b) In the given system,
$a = \frac{m_{1} - m_{2}}{m_{1} + m_{2}} = \frac{g}{8}$
$	herefore\ \ \frac{m_{1} - m_{2}}{m_{1} + m_{2}} = \frac{1}{8}$
$8m_{1} - 8m_{2} = m_{1} + m_{2}$
$7m_{1} = 9m_{2}$
$\frac{m_{1}}{m_{2}} = \frac{9}{7}$

Q. A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is ($g/8$), then the ratio of masses is

Explanation

Reviewed by Dr. Abubacker

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