Q. Three equal weights $A,\ B$ and $C$ of mass $2\ kg$ each are hanging on a string passing over a fixed frictionless pulley as shown in the figure. The tension in the string connecting weights $B$ and $C$ is

A) Zero
B) $13\ N$
C) $3.3\ N$
D) $19.6\ N$
Explanation

(b) Tension between $m_{2}$ and $m_{3}$ is given by
$T = \frac{2m_{1}m_{3}}{m_{1} + m_{2} + m_{3}} \times g$
$= \frac{2 \times 2 \times 2}{2 + 2 + 2} \times 9.8 = 13\ N$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Laws Of Motion MCQs