Two blocks are in contact on a frictionless table. One has mass $m$ and other 2$m$. A force $f$ is applied on 2$m$ as shown in figure. Next the same force $F$ is applied from the right on $m$. In the two cases respectively, the force of contact between the two blocks will be [image:5_image42.emf]

Question

Dr. Abubacker · Accepted Answer

(c) When force $F$ is applied on 2$m$ from left, contact force,
$F_{1} = \frac{m}{m + 2m}F = \frac{F}{3}$
When force $F$ is applied on $m$ from right, contact force
$F_{2} = \frac{2m}{m + 2m}F = \frac{2F}{3}$
$	herefore$ $F_{1}:F_{2} = 1\ :2$

Q. Two blocks are in contact on a frictionless table. One has mass $m$ and other 2$m$. A force $f$ is applied on 2$m$ as shown in figure. Next the same force $F$ is applied from the right on $m$. In the two cases respectively, the force of contact between the two blocks will be

Explanation

Reviewed by Dr. Abubacker

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