A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is $g/8$ then the ratio of the masses is

Question

Dr. Abubacker · Accepted Answer

(b) $a = \left( \frac{m_{1} - m_{2}}{m_{1} + m_{2}} \right)g \Rightarrow \frac{g}{8} = \left( \frac{m_{1} - m_{2}}{m_{1} + m_{2}} \right)g \Rightarrow \frac{m_{1}}{m_{2}} = \frac{9}{7}$

Q. A light string passing over a smooth light pulley connects two blocks of masses $m_{1}$ and $m_{2}$ (vertically). If the acceleration of the system is $g/8$ then the ratio of the masses is

Explanation

Reviewed by Dr. Abubacker

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