Q. A body of mass 10 kg is acted upon by two forces each of magnitude 10 N making an angle of $60{^\circ}$ with each other. Find the net acceleration of the body
A) $2\sqrt{3}{ms}^{- 2}$
B) $\sqrt{3}{ms}^{- 2}$
C) $3\sqrt{3}{ms}^{- 2}$
D) $4\sqrt{3}{ms}^{- 2}$
Explanation
(b) Resultant force $F_{net} = \sqrt{F_{1}^{2} + F_{2}^{2} + 2F_{1}F_{2}\cos\theta}$
$= \sqrt{(10)^{2} + (10)^{2} + 2 \times 10 \times 10 \times \cos{60{^\circ}}}$
$= \sqrt{100 + 100 + 100} = 10\sqrt{3}$
Mass of the body =10 kg
$\therefore\ \ Acceleration = \frac{force}{mass}$
$= \frac{10\sqrt{3}}{10} = \sqrt{3}\ {ms}^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.