Q. When force $F_{1},F_{2},F_{3}$ are acting on a particle of mass $m$ such that $F_{2}$ and $F_{3}$ are mutually perpendicular, then the particle remains stationary. If the force $F_{1}$ is now removed, then the acceleration of the particle is
A) $F_{1}/m$
B) $F_{2}F_{3}/mF_{1}$
C) ${(F}_{2} - F_{3})/m$
D) $F_{2}/m$
Explanation
(a) As $F_{2}$ and $F_{3}$ are mutually perpendicular, their resultant $= \sqrt{F_{2}^{2} + F_{3}^{2}}$
As particle is stationary under $F_{1},F_{2},F_{3}$, therefore, =$\sqrt{F_{2}^{2} + F_{3}^{2}}$ must be equal and opposite to $F_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.