Q. A body of $10\ kg$ is acted by a force of $129.4\ N$ if $g = 9.8\ m/s^{2}$. The acceleration of the block is $10\ m/s^{2}$. What is the coefficient of kinetic friction
A) 0.03
B) 0.01
C) 0.30
D) 0.25
Explanation
(c) Net force on the body = Applied force $-$ Friction
$ma = F - \mu_{k}mg \Rightarrow \mu_{k} = \frac{F - ma}{mg} = \frac{129.4\ - 10 \times 10}{10 \times 9.8} = 0.3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.