Q. A vehicle of $100\ kg$ is moving with a velocity of $\ 5\ m/sec$. To stop it in $\frac{1}{10}\ sec$, the required force in opposite direction is
A) $5000\ N$
B) $500\ N$
C) $50\ N$
D) $1000\ N$
Explanation
(a) $F = m\left( \frac{dv}{dt} \right) = \frac{100 \times 5}{0.1} = 5000\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.