Q. A block is kept on a frictionless inclined surface with angle of inclination ‘$\alpha$’. The incline is given an acceleration ‘$a$’ to keep the block stationary. Then $a$ is equal to
A) $g$
B) $g\tan\alpha$
C) $g/\tan\alpha$
D) $g\ cosec\ \alpha$
Explanation
(b) Let the mass of a block is $m$. It will remains stationary if forces acting on it are in equilibrium $i.e$, $ma\cos\alpha = mg\sin\alpha\ \Rightarrow a = g\tan\alpha$
Here $ma =$ Pseudo force on block , $mg =$ Weight
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.