(a) Change in momentum [image:5_image187.emf] $\mathrm{\Delta}p = 2\ mu\sin{30{^\circ}}$ $= 2 \times 0.1 \times 10 \times \frac{1}{2}$ $= 1$ kg-$ms^{- 1}$ $F_{av} = \frac{\mathrm{\Delta}p}{\mathrm{\Delta}t} = \frac{1}{0.1} = 10$N
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