Q. 100 g of an iron ball having velocity 10$\ ms^{- 1}$ collides with wall at an angle 30${^\circ}$ and rebounds with the same angle. If the period of contact between the ball and wall is 0.1 s, then the average force experienced by the wall is

A) 10 N
B) 100 N
C) 1.0 N
D) 0.1 N
Explanation

(a) Change in momentum
[image:5_image187.emf]
$\mathrm{\Delta}p = 2\ mu\sin{30{^\circ}}$
$= 2 \times 0.1 \times 10 \times \frac{1}{2}$
$= 1$ kg-$ms^{- 1}$
$F_{av} = \frac{\mathrm{\Delta}p}{\mathrm{\Delta}t} = \frac{1}{0.1} = 10$N

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Laws Of Motion MCQs