Q. A $500\ kg$ horse pulls a cart of mass $1500\ kg$ along a level road with an acceleration of $1\ ms^{- 2}$. If the coefficient of sliding friction is 0.2, then the force exerted by the horse in forward direction is
A) $3000\ N$
B) $4000\ N$
C) $5000\ N$
D) $6000\ N$
Explanation
(d) Net force in forward direction = Accelerating force + Friction
$= ma + \mu\ mg = m(a + \mu\ g) = (1500 + 500)(1 + 0.2 \times 10)$
$= 2000 \times 3 = 6000\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.