Q. A diwali rocket is ejecting $0.05\ kg$ of gases per second at a velocity of $400\ m/sec$. The accelerating force on the rocket is
A) $20\ dynes$
B) $20\ N$
C) $22\ dynes$
D) $1000\ N$
Explanation
(b) $F = u\left( \frac{dm}{dt} \right) = 400 \times 0.05 = 20\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.