Q. A block of mass $M$ is pulled along a horizontal frictionless surface by a rope of mass$\ m$. If a force $P$ is applied at the free end of the rope, the force exerted by the rope on the block is
A) $\frac{Pm}{M + m}$
B) $\frac{Pm}{M - m}$
C) $P$
D) $\frac{PM}{M + m}$
Explanation
(d) Let acceleration of system (rope + block) is $a$ which acting along the direction of applied force. Then
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Where, $T$ is the required parameter.
For block $T = Ma$
$\Longrightarrow \ \ T = \frac{MP}{M + m}\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.