A block $B$ is pushed momentarily along a horizontal surface with an initial velocity$\ v$. If $\mu$ is the coefficient of sliding friction between $B$ and the surface, block $B$ will come to rest after a time [image:5_image49.jpeg]

Question

Dr. Abubacker · Accepted Answer

(a) Block B will come to rest, it force applied to it will vanish due to frictional force acting between block B and surface $ie,$
$force\ applied = frictional\ force$
$ie,\ \ \mu\ mg = ma$
$or\ \ \ \ \ \ \ \ \ \mu\ mg = m\left( \frac{v}{t} \right)$
$or\ \ \ \ \ t = \frac{v}{\mu\ g}$

Q. A block $B$ is pushed momentarily along a horizontal surface with an initial velocity$\ v$. If $\mu$ is the coefficient of sliding friction between $B$ and the surface, block $B$ will come to rest after a time

Explanation

Reviewed by Dr. Abubacker

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