Q. If a block slides down a plane inclined at $30{^\circ}$ with horizontal, then the coefficient of friction between the block and inclined plane is
A) 0.5
B) $\frac{1}{3}$
C) $\frac{1}{\sqrt{2}}$
D) $\frac{1}{\sqrt{3}}$
Explanation
(d) We know that,
$\mu = \tan\theta$
$\therefore\ \ = \tan{30{^\circ}} = \frac{1}{\sqrt{3}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.