Q. $300\ joule$ of work is done in sliding up a $2\ kg$ block on an inclined plane to a height of $10\ metres$. Taking value of acceleration due to gravity ‘$g$’ to be $10\ m/s^{2}$, work done against friction is
A) $100\ J$
B) $200\ J$
C) $300\ J$
D) Zero
Explanation
(a) Work done against gravity $= mgh = 2 \times 10 \times 10 = 200\ J$
Work done against friction $= (Total\ work\ done - work\ done\ against\ gravity) = 300 - 200 = 100\ J$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.