A solid disc of mass $M$ is just held in air horizontally by throwing $40$ stones per $\sec$ vertically upwards to strike the disc each with a velocity $6\ ms^{- 1}$. If the mass of each stone is $0.05\ kg$ what is the mass of the disc $(g = 10ms^{- 2})$

Question

Dr. Abubacker · Accepted Answer

(a) Weight of the disc will be balanced by the force applied by the bullet on the disc in vertically upward direction
$F = nmv = 40 	imes 0.05 	imes 6 = Mg$
$\Rightarrow M = \frac{40 	imes 0.05 	imes 6}{10} = 1.2\ kg$

Q. A solid disc of mass $M$ is just held in air horizontally by throwing $40$ stones per $\sec$ vertically upwards to strike the disc each with a velocity $6\ ms^{- 1}$. If the mass of each stone is $0.05\ kg$ what is the mass of the disc $(g = 10ms^{- 2})$

Explanation

Reviewed by Dr. Abubacker

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