Q. A light string passes over a frictionless pulley. To one of its ends a mass of $6\ kg$ is attached. To its other end a mass of $10\ kg$ is attached. The tension in the thread will be
A) $24.5\ N$
B) $2.45\ N$
C) $79\ N$
D) $73.5\ N$
Explanation
(d) $T = \frac{2m_{1}m_{2}}{m_{1} + m_{2}}g = \frac{2 \times 10 \times 6}{10 + 6} \times 9.8 = 73.5\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.