Q. A player caught a cricket ball of mass 150 g moving at the rate of $20\ {ms}^{- 1}$. If the catching process be completed in 0.1 s, the force of blow exerted by the ball on the hands of the player is

A) 0.3 N
B) 30 N
C) 300 N
D) 3000 N
Explanation

(b) Force,
$\ F = \frac{m(u - v)}{t} = \frac{150 \times 10^{- 3}(20 - 0}{0.1}$
$= 30\ N$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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