Q. A cricket ball of mass 150 g collides straight with a bat with a velocity of 10$\ ms^{- 1}$ . Batsman hits it straight back with a velocity of 20$\ ms^{- 1}$. If ball remains in contact with bat for 0. 1s, then average force exerted by the bat on the ball is
A) 15 N
B) 45 N
C) 150 N
D) 4.5 N
Explanation
(b) $F = \frac{m(v - u)}{t} = \frac{0.15\lbrack 20 - ( - 10)\rbrack}{0.1} = \frac{0.15 \times 30}{0.1} = 45$N
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.