Q. A body of $5\ kg$ weight kept on a rough inclined plane of angle $30{^\circ}$ starts sliding with a constant velocity. Then the coefficient of friction is (assume $g = 10\ m/s^{2}$)
A) $1/\sqrt{3}$
B) $2/\sqrt{3}$
C) $\sqrt{3}$
D) $2\sqrt{3}$
Explanation
(a) $\mu = \tan{30{^\circ}} = \frac{1}{\sqrt{3}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.