Q. Pulling force making an angle $\theta$ to the horizontal is applied on a block of weight $W$ placed on a horizontal table. If the angle of friction is $\alpha$, then the magnitude of force required to move the body is equal to
A) $\frac{W\sin\alpha}{g\tan{(\theta - \alpha)}}$
B) $\frac{W\cos\alpha}{\cos{(\theta - \alpha)}}$
C) $\frac{W\sin\alpha}{\cos{(\theta - \alpha)}}$
D) $\frac{W\tan\alpha}{\sin{(\theta - \alpha)}}$
Explanation
The correct answer is Option C: $\frac{W\sin\alpha}{\cos{(\theta - \alpha)}}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.