Q.
Two blocks, $4\ kg$ and $2\ kg$ are sliding down an incline plane as shown in figure. The acceleration of $2\ kg$ block is
A) $1.66\ m/s^{2}$
B) $2.66\ m/s^{2}$
C) $3.66\ m/s^{2}$
D) $4.66\ m/s^{2}$
Explanation
(b) Let contact force $= R$
[image:5_image204.emf]
$m_{1}g\sin\alpha - R - \mu_{1}N_{1} = m_{1}a$ …(i)
$R = \frac{\left( \mu_{2} - \mu_{1} \right)m_{1}m_{2}g\cos\alpha}{\left( m_{1} + m_{2} \right)}$
$\Rightarrow R = \frac{0.1 \times 8 \times 9.8 \times \sqrt{\frac{3}{2}}}{6}$ …(ii)
On simplify equation (i) and (ii),
$a = 2.646\ m/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.