Q. A rope of length $5\ m$ is kept on frictionless surface and a force of $\ 5N$ is applied to one of its end. Find tension in the rope at $1\ m$ from this end
A) $1\ N$
B) $3\ N$
C) $4\ N$
D) $5\ N$
Explanation
(c) $T = \frac{F(L - x)}{L} = \frac{5(5 - 1)}{5} = 4N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.