A particle moves in $x$-$y$ plane under the action of force F and the value of its linear momentum p at a given time $t$ is $p_{x} = 2\cos t,\ p_{y} = 2\sin t$. Then the angle $ heta$ between F and p at a given time $t$ is

Question

A particle moves in $x$-$y$ plane under the action of force F and the value of its linear momentum p at a given time $t$ is $p_{x} = 2\cos t,\ p_{y} = 2\sin t$. Then the angle $	heta$ between F and p at a given time $t$ is

Dr. Abubacker · Accepted Answer

(d) The linear momentum of the particle will be
$p = \sqrt{p_{x}^{2} + p_{y}^{2}} = 2\sqrt{\cos^{2}\ t + \sin^{2}}\ t = 2\ unit$
It the clear that $p$ is constant hence, the angle between F and p is $90{^\circ}$ .

Q. A particle moves in $x$-$y$ plane under the action of force F and the value of its linear momentum p at a given time $t$ is $p_{x} = 2\cos t,\ p_{y} = 2\sin t$. Then the angle $\theta$ between F and p at a given time $t$ is

Explanation

Reviewed by Dr. Abubacker

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