Q. A block of mass ‘$m$’ is connected to another block of mass ‘$M$’ by a spring (massless) of spring constant ‘$K$’. The blocks are kept on a smooth horizontal plane. Initially the blocks are at rest and the spring is unstretched. Then a constant force ‘$F$’ starts acting on the block of mass ‘$M$’ to pull it. Find the force on the block of mass ‘$m$’
A) $\frac{mF}{M}$
B) $\frac{(M + mF)}{m}$
C) $\frac{mF}{(m + M)}$
D) $\frac{MF}{(m + M)}$
Explanation
(c) Acceleration of the system $= \frac{F}{M + m}$ and
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Force on the block $m = Kx = ma = \frac{mF}{m + M}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.