Q. The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘$a$’ is $3:2$,. The value of ‘$a$’ is ($g$- Acceleration due to gravity of the earth)
A) $\frac{3}{2}g$
B) $\frac{g}{3}$
C) $\frac{2}{3}g$
D) $g$
Explanation
(b) $\frac{mg}{m(g - a)} = \frac{3}{2} \Rightarrow a = g/3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.