A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of $\ 5{\ ms}^{- 2}$ , the reading of the spring balance will be

Question

Dr. Abubacker · Accepted Answer

(a) In stationary position,
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Spring balancing reading
$= mg = 49$
$m = \frac{49}{9.8} = 5kg$
When lift moves downward,
$mg - T = ma$
Reading of balance
$T = mg - ma$
$= 5(9.8 - 5) = 5 	imes 4.8 = 24.0\ N$

Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of $\ 5{\ ms}^{- 2}$ , the reading of the spring balance will be

Explanation

Reviewed by Dr. Abubacker

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