Q. A block of mass $M$ is pulled along a horizontal frictionless surface by a rope of mass $m.$ Force $P$ is applied at one end of the rope. The force which the rope exerts on the block is
A) $\frac{P}{M(m + M)}$
B) $\frac{P}{M - m}$
C) $\frac{Pm}{M - m}$
D) $\frac{PM}{m + M}$
Explanation
(d) Acceleration $= \frac{P}{M + m}$
Force on the block = Mass of block $\times$ acceleration
$= \frac{MP}{M + m}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.