Three blocks of masses $m_{1},\ m_{2}$ and $m_{3}$ are connected by massless strings as shown on a frictionless table. They are pulled with a force $T_{3} = 40\ N$. If $m_{1} = 10\ kg,\ m_{2} = 6\ kg$ and$\ m_{3} = 4\ kg$, the tension $T_{2}\ $will be

Question

Dr. Abubacker · Accepted Answer

(d) $T_{2} = \left( m_{1} + m_{2} ight) 	imes \frac{T_{3}}{m_{1} + m_{2} + m_{3}} = \frac{(10 + 6) 	imes 40}{20} = 32\ N$

Q. Three blocks of masses $m_{1},\ m_{2}$ and $m_{3}$ are connected by massless strings as shown on a frictionless table. They are pulled with a force $T_{3} = 40\ N$. If $m_{1} = 10\ kg,\ m_{2} = 6\ kg$ and$\ m_{3} = 4\ kg$, the tension $T_{2}\ $will be

Explanation

Reviewed by Dr. Abubacker

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