Q. A block at rest slides down a smooth inclined plane which makes an angle $60{^\circ}$ with the vertical and it reaches the ground in $t_{1}$ second. Another block is dropped vertically from the same point and reaches the ground in $t_{2}$ second. Then the ratio of $t_{1}:t_{2}$ is

A) 1:2
B) 2:1
C) 1:3
D) $1:\sqrt{2}$
Explanation

(b) $l = \frac{1}{2}g\cos{60{^\circ}\ t_{1}^{2}\ \ \ \ldots.(i)}$
$lcos\theta = \frac{1}{2}gt_{2}^{2}\ \ \ldots(ii)$
$\frac{t_{1}^{2}}{t_{2}^{2}} = \frac{1}{\cos^{2}60{^\circ}}$
$= \frac{1}{4}$
$t_{1}:t_{2} = 2:1$
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Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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