(c) Various forces acting on the ball are as shown in figure. The three concurrent forces are in equilibrium. Using Lami’s theorem
$\frac{T_{1}}{\sin{150{^\circ}}} = \frac{T_{2}}{\sin{120{^\circ}}}$
$= \frac{10}{\sin{90{^\circ}}}$
$\frac{T_{1}}{\sin{30{^\circ}}} = \frac{T_{2}}{\sin{60{^\circ}}} = \frac{10}{1}$
$\therefore T_{1} = 10\sin 30{^\circ}$
$= 10 \times 0.5 = 5$N
$T_{2} = 10\sin{60{^\circ}}$
and $= 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}\ $N