Two blocks of masses $m_{1} = 4$ kg and $m_{2} = 2$ kg are connected to the ends of a string which passes over a massless, frictionless pulley. The total downwards thrust on the pulley is nearly

Question

Dr. Abubacker · Accepted Answer

(b) $T = \frac{2m_{1}m_{2}}{m_{1} + m_{2}}g = \frac{2 	imes 4 	imes 2 	imes 10}{4 + 2}$
$= \frac{160}{6} = 26.6 = 27\ N$
Total downward thrust on the pulley
$= 2T = 2 	imes 27 = 54$ N

Q. Two blocks of masses $m_{1} = 4$ kg and $m_{2} = 2$ kg are connected to the ends of a string which passes over a massless, frictionless pulley. The total downwards thrust on the pulley is nearly

Explanation

Reviewed by Dr. Abubacker

Want more practice?