Q. A player kicks a football of mass 0.5 kg and the football begins to move with a velocity of 10 m/s. If the contact between the leg and the football lasts for $\frac{1}{50}s,\ $ then the force on the ball should be

A) 2500 N
B) 1250 N
C) 250 N
D) 625 N
Explanation

(c) $Force\ on\ the\ football,$
$F = \frac{md\ v}{dt}$
$F = \frac{m(v_{2} - v_{1})}{dt} = \frac{0.5(10 - 0)}{1/50} = 250\ N$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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