Q.
Refer to the system shown in figure. The ratio of tension $T_{1}$ and $T_{2}$ is
A) $\frac{m_{1}}{m_{1} + m_{2}}$
B) $\frac{m_{2}}{m_{1} + m_{2}}$
C) $\frac{m_{1}}{m_{2}}$
D) $\frac{m_{2}}{m_{1}}$
Explanation
(a) $T_{2} - T_{1} = m_{2}a$
[image:5_image215.emf]
Dividing, $\frac{T_{2} - T_{1}}{T_{1}} = \frac{m_{2}}{m_{1}}$
or $\frac{T_{2}}{T_{1}} = \frac{m_{2}}{m_{1}} + 1 = \frac{{m_{2} + m}_{1}}{m_{1}}$
or $\frac{T_{2}}{T_{1}} = \frac{m_{1}}{m_{1} + m_{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.