Q. A block moving on a surface with velocity $20\ {ms}^{- 1}$ comes to rest because of surface friction over a distance of 40 m. taking $g = {10\ ms}^{- 2}$, the coefficient of dynamic friction is

A) 0.5
B) 0.3
C) 0.2
D) 0.1
Explanation

(a) [image:5_image218.jpeg]
From equation of motion
$v^{2} = u^{2} - 2as$
Where $v$ is final velocity, $u$ the initial velocity, $a$ acceleration and $s$ the displacement.
Given, $\ v = 0,u = 20\ {ms}^{- 1},\ s = 40\ m$
$\therefore\ \ \ 0 = (20)^{2} - 2 \times 40 \times a$
$\Longrightarrow \ \ a = 5\ {ms}^{- 2}$
Kinetic (or dynamic) friction occurs when two objects are moving relative to each other and rub together. It is given by
$\mu_{x} = \frac{a}{g} = \frac{5}{10} = 0.5\ $

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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