Q. An army vehicle of mass $1000\ kg$ is moving with a velocity of $10\ m/s$ and is acted upon by a forward force of $1000\ N$ due to the engine and a retarding force of $500\ N$ due to friction. What will be its velocity after $10\ s$
A) $5\ m/s$
B) $10\ m/s$
C) $15\ m/s$
D) $20\ m/s$
Explanation
(c) $v = u + \frac{F}{m}t = 10 + \left( \frac{1000 - 500}{1000} \right) \times 10 = 15\ m/s$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.