Q. A block of mass $m$ is connected to another block of mass $M$ by a spring (massless) of spring constant$\ k$. The blocks are kept on a smooth horizontal plane. Initially the blocks are at rest and the spring is unstretched. Then a constant force $F$ starts acting on the block of mass $M$ to pull it. Find the force on the block of mass $m$
A) $\frac{mF}{M}$
B) $\frac{(M + m)F}{m}$
C) $\frac{mF}{(m + M)}$
D) $\frac{MF}{(m + M)}$
Explanation
(c) $Acceleration\ of\ system,\ a = \frac{F}{m + M}$
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So, force acting on mass
$\ m = ma = \frac{mF}{m + M}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.