Q. A block of mass $m$ is placed on a smooth inclined plane of inclination $\theta$ with the horizontal. The force exerted by the plane on the block has a magnitude
A) $mg$
B) $\frac{mg}{\cos\theta}$
C) $mg\cos\theta$
D) $mg\tan\theta$
Explanation
(c) Component of weight $mg$ in a direction perpendicular to the inclined plane is $mg\cos\theta$. According to Newton’s third law of motion, the force exerted by the plane on the block is $mg\cos\theta$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.