Q. A block of mass $10\ kg$ is placed on a rough horizontal surface having coefficient of friction $\mu = 0.5$. If a horizontal force of $100\ N$ is acting on it, then acceleration of the block will be
A) $0.5\ m/s^{2}$
B) $5\ m/s^{2}$
C) $10\ m/s^{2}$
D) $15\ m/s^{2}$
Explanation
(b) $a = \frac{Applied\ force - Kinetic\ friction}{mass}$
$= \frac{100 - 0.5 \times 10 \times 10}{10} = 5\ m/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.