Q.
The acceleration of the system shown in figure is
A) $\frac{3.5}{17.5}g$
B) $\frac{7.5}{17.5}g$
C) $\frac{14.5}{17.5}g$
D) $\frac{g}{7}$
Explanation
(d) Refer to the free-body diagrams
[image:5_image228.emf]
$T - 10g\sin{30{^\circ} = 10a}\ \ $or $T - 5g = 10a$
Again , $7.5 - T = 7.5\alpha$
Adding, $2.5g = 17.5\alpha$
or $\alpha = \frac{25g}{175} = \frac{g}{7}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.