Q. A body of mass $5\ kg$ is suspended by a spring balance on an inclined plane as shown in figure. The spring balance measure
A) $50\ N$
B) $25\ N$
C) $500\ N$
D) $10\ N$
Explanation
(b) Since downward force along the inclined plane
$= mg\sin\theta = 5 \times 10 \times \sin{30{^\circ} = 25N}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.