
(c) From force diagram shown in figure,
$T = mg$..(i)
$and\ \ 2T\cos{\theta = \sqrt{2}}mg\ \ \ldots(ii)\ $
[image:5_image232.jpeg]
Combing Eqs. (i) and (ii), we have
$2mg\cos{\theta = \sqrt{2}\ mg}$
$or\cos{\theta = \frac{1}{\sqrt{2}}}$
$or\ \theta = 45{^\circ}$