Q. A particle of mass $0.3\ kg$ is subjected to a force $F = - kx$ with $k = 15\ N/m$. What will be its initial acceleration if it is released from a point $20\ cm$ away from the origin
A) $5\ m/s^{2}$
B) $10\ m/s^{2}$
C) $3\ m/s^{2}$
D) $15\ m/s^{2}$
Explanation
(b) Force on particle at $20\ cm$ away $F = kx$
$F = 15 \times 0.2 = 3N$ [As $k = 15\ N/m\rbrack$
$\therefore$ Acceleration $= \frac{Force}{Mass} = \frac{3}{0.3} = 10\ m/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.