Q. If a bullet of mass $5\ gm$ moving with velocity $100\ m/sec$, penetrates the wooden block upto $6\ cm$. Then the average force imposed by the bullet on the block is
A) $8300\ N$
B) $417\ N$
C) $830\ N$
D) Zero
Explanation
(b) $u = 100\ m/s,\ v = 0,\ s = 0.06\ m$
Retardation $= a = \frac{u^{2}}{2s} = \frac{(100)^{2}}{2 \times 0.06} = \frac{1 \times 10^{6}}{12}$
$\therefore$ Force $= ma = \frac{5 \times 10^{- 3} \times 1 \times 10^{6}}{12} = \frac{5000}{12} = 417\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.