Q.
In the figure shown, $m_{1} = 10\ kg,\ {\ m}_{2} = 6\ kg,\ \ m_{3} = 4\ kg.$ If $T_{3} = 40\ N,\ \ T_{2} = ?$
A) 13 N
B) 32 N
C) 25 N
D) 35 N
Explanation
(b) Let $a$ be the acceleration of each block. Then,
$T_{3} = \left( m_{1} + m_{2} + m_{3} \right)a\ \ \ \ \ldots.(i)$
$and\ \ \ T_{2} = \left( m_{1} + m_{2} \right)a\ \ldots.(ii)$
from Eq. (i) and (ii), we get
$T_{2} = \left( \frac{m_{1} + m_{2}}{m_{1} + m_{2} + m_{3}} \right) \times T_{3}$
$= \left( \frac{10 + 6}{10 + 6 + 4} \right) \times 40 = 32\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.