Q. A man slides down on a telegraphic pole with acceleration equal to one-fourth of acceleration due to gravity. The frictional force between man and pole is equal to in terms of man’s weight $w$
A) $\frac{w}{4}$
B) $\frac{w}{2}$
C) $\frac{3w}{4}$
D) $w$
Explanation
(c) Man is sliding down the telegraphic pole with acceleration$\ g/4$. So,
$mg - F = \frac{mg}{4}$
$\Longrightarrow F = mg - \frac{mg}{4}$
$\Longrightarrow F = \frac{3mg}{4}$
$\Longrightarrow F = \frac{3w}{4}$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.